How do I do something like:
if !("abc" in file1 and "def" in file2)
then
echo "Failed"
fi
I've already known how to check "abc" in file1: grep -Fxq "abc" file1, but I can't manage to get the if not (command1 and command2) part to work.
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1Use De-morgans law - en.wikipedia.org/wiki/De_Morgan's_laws - i.e. "not(A and B)" becomes "not A or not B"Ed Heal– Ed Heal2013-03-14 11:42:57 +00:00Commented Mar 14, 2013 at 11:42
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Thanks, the problem is I don't know how to write it using bash script...pckben– pckben2013-03-14 11:48:13 +00:00Commented Mar 14, 2013 at 11:48
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3 Answers
You got it almost right. Just add a space between the exclamation mark and the grep commands, and it would work:
if ! (grep -Fxq "abc" file1 && grep -Fxq "def" file2); then
echo "Failed"
fi
Assuming bash, there is no need for extra else.
Note that using parenthesis runs the greps in a subshell environment, as a child shell process. You can easily avoid this by using curly braces (this thing is called group command):
if ! { grep -Fxq "abc" file1 && grep -Fxq "def" file2; }; then
echo "Failed"
fi
Note that you need more spaces and an additional semicolon – isn't bash syntax just so funny!?!
1 Comment
FooF
What specifically does not work? Are you using
bash ({ ... } construct is bash extension)?You could do:
$ grep -Fxq "abc" file1 && grep -Fxq "def" file2 || echo "Failed"
This uses the bash logical operators AND && and OR ||.
This can be split over multiple lines like:
$ grep -Fxq "abc" file1 &&
> grep -Fxq "def" file2 ||
> echo "Failed"
Comments
if (grep -Fxq "abc" file1 && grep -Fxq "def" file2);
then
echo ""
else
echo "failed"
fi
