I have byte array that consist of hex values like CA ,FA,21,33
But I want to list them in JList as a single element CAFA2133.
In order to list them in JList I think I need to convert it to string.
So any recommendation?
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8 Answers
public static String bytesToHex(byte[] in) {
final StringBuilder builder = new StringBuilder();
for(byte b : in) {
builder.append(String.format("%02x", b));
}
return builder.toString();
}
Comments
You need to look at String.format() and the Formatter specifications.
e.g.
String.format("%02x", byteValue);
Iterate through the array and append each String.format() result to a StringBuilder
3 Comments
andrei
Nice and simple. No need for me to sift through the wall of text on the other duplicate question and answers :)
darkled
it works, but it takes about 3 times longer than the method below based on byte operations
Brian Agnew
Interesting. Can you link to the specific answer below ?
How about:
public static String bytesToHex(byte[] bytes) {
final char[] hexArray = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
char[] hexChars = new char[bytes.length * 2];
int v;
for ( int j = 0; j < bytes.length; j++ ) {
v = bytes[j] & 0xFF;
hexChars[j * 2] = hexArray[v >>> 4];
hexChars[j * 2 + 1] = hexArray[v & 0x0F];
}
return new String(hexChars);
}
This method should do that for you..pass in the byte array as a parameter to return the hex string...
private static String convertToHexString(byte[] data) {
StringBuffer buf = new StringBuffer();
for (int i = 0; i < data.length; i++) {
int halfbyte = (data[i] >>> 4) & 0x0F;
int two_halfs = 0;
do {
if ((0 <= halfbyte) && (halfbyte <= 9))
buf.append((char) ('0' + halfbyte));
else
buf.append((char) ('a' + (halfbyte - 10)));
halfbyte = data[i] & 0x0F;
} while(two_halfs++ < 1);
}
return buf.toString();
}
hope that helps..
Comments
You could use Integer.toStringint i, int radix) to convert each of your numbers into a string in hexadecimal, and then concatenate them together. Now you just have to get your bytes into an int.
Comments
Refer to Integer's toHexString.
Converting your byte to int and then obtaining the resulting String should do the trick.
Of course, you would have to concatenate the Strings with a StringBuilder then.
Comments
import java.util.HashMap;
public class NumUtil
{ private static HashMap<Byte,char[]>byteToHex=new HashMap<Byte, char[]>();
static
{ for(int i=0;i<16;++i)
byteToHex.put((byte)i, new char[]{'0',Integer.toHexString(i).charAt(0)});
for(int i=16;i<256;++i)
byteToHex.put((byte)i, Integer.toHexString(i).toCharArray());
}
public static String toHexString(byte[]bytes)
{ StringBuilder stringBuilder = new StringBuilder(bytes.length*2);
for(byte b:bytes)
stringBuilder.append(byteToHex.get(b));
return stringBuilder.toString();
}
}
Comments
If this array is 4 bytes long, you could probably concatenate bytes and make use of Integer.toString(int, int) method.
byte[] array = /* initialization */;
int x = 0;
for (int i = 0, l = Math.min(array.length, 4); i < l; i++) {
x <<= 8;
x |= (array[i] & 0xFF);
}
String hex = Integer.toString(x, 16);
