Extracting and parsing using python

Question

I have these two lines in the format

VP VB go
NP PRP$ your NN left

saved in a text file. I want to access this text file and then print this following result in a new text file

NP NN left

Help me how to this using python.

Thanks for any help in advance

On what basis are we suppose to select NP NN left from the text file? Without such an explanation, print('NP NN left') is a valid solution. — unutbu
– unutbu, Commented Mar 16, 2013 at 22:19
@unutbu I want to print this for all those pattern which have NP in the beginning of the line and NN before a word in that same line. — Mcolorz
– Mcolorz, Commented Mar 16, 2013 at 22:26

Karmel · Accepted Answer · 2013-03-16 23:02:01Z

1

If I am interpreting you correctly, you want all cases of

NP NN word

in which case you could use a regex expression that looks for NP, NN, and the subsequent word:

import re
f = open('file.txt')
regex = r'^(NP).*?(NN) (\w+).*?$'
for line in f:
    try: ' '.join(re.search(regex, line).groups())
    except AttributeError: pass

answered Mar 16, 2013 at 23:02

Karmel

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kren470 · Accepted Answer · 2013-03-16 23:03:14Z

0

Edit: is this better?

f=open("myfile")
#read all lines of the file and remove newline characters
a=[i.strip() for i in f.readlines()]
f.close()

for i in a:
  i=i.split()
  n=-1
  try:
    n=i.index("NN")
  except:
    pass
  if n!=-1 and n!=len(i)-1 and i[0]=="NP":
    print i[0], i[n], i[n+1]

edited Mar 16, 2013 at 23:03

answered Mar 16, 2013 at 22:46

kren470

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1 Comment

Mcolorz Over a year ago

the file have 1000 lines of those types and the number of words between NP and NN is not fixed so printing using array by giving index and specifying that a in first line won't be that possible

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