creating a dynamic array?

Question

    keyMain= new Key_Node[X];
    for(int i=0; i<X; i++)
    {
        keyMain[i].key=i;
        cout << keyMain[i].key<<endl;
        keyMain[i].next_package=NULL;
    }

Am I doing it right here? I am not sure about it. It seems like the right thing to do, but can anybody confirm? Thank you.X is the number inputted by the user.

paxdiablo · Accepted Answer · 2013-03-17 03:43:46Z

3

Yes, you can certainly do that, provided the array is not expected to grow or shrink.

Otherwise, std::vector (see here) is probably a better choice. C++ provides some powerful collection classes in its standard library and everyone who professes to know the language should be familiar with them.

answered Mar 17, 2013 at 3:43

paxdiablo

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2 Comments

user2155612 Over a year ago

No, the array will be static throughout the course of the program. So my code would work, right?

paxdiablo Over a year ago

Yes, it would work as-is, given your comment. Just be careful of using the word static (unchanging) - "static" has a specific meaning in C++ unrelated to its common definition.

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