custom math function using php

Question

I'm not so good with PHP. I have a function which I'm trying to execute, but am unable to do so. I'm trying this for quite some time now.

$init_val = ($price/120) * 20;
$mid_val = $price - $init_val;
//$final_value = $mid_value - 35% of $mid_val     // want to execute this logic
//$final_value = $mid_value - ($mid_val * 35%);   // this gives error
//$final_value = $mid_value - 35%;                // same error

The error given is:

PHP Parse error: syntax error, unexpected ';' in /var/www/site1/function.php on line 51

What am I doing wrong?

Use $mid_val * 0.35. % is for mod.

Antony
– Antony

2013-03-20 08:26:42 +00:00
Commented Mar 20, 2013 at 8:26 — Antony
– Antony, Commented Mar 20, 2013 at 8:26

Matt Cain · Accepted Answer · 2013-03-20 08:27:16Z

3

You can't use percentage values like that in PHP. The % symbol is reserved for modulus operations. Try this instead:

$final_value = $mid_value - ($mid_val * 0.35);

That would give you 65% of $mid_value in $final_value

answered Mar 20, 2013 at 8:27

Matt Cain

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1 Comment

Ajit S Over a year ago

Thank you for giving the right answer and also explaining where I was going wrong :)

Mihai Iorga · Accepted Answer · 2013-03-20 08:26:31Z

3

You cannot use % as a math function:

$final_value = $mid_value - ($mid_val * 0.35);

answered Mar 20, 2013 at 8:26

Mihai Iorga

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Rob · Accepted Answer · 2013-03-20 08:26:17Z

1

$final_value = $mid_value - ($mid_val * 0.35);

answered Mar 20, 2013 at 8:26

Rob

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Déjà vu · Accepted Answer · 2013-03-20 08:30:33Z

1

If you want to code the idea of percent, create a function

function percent($value) {
    return $value / 100;
}

then you can write

$final_value = $mid_value - $mid_val * percent(35);

(no need of parentheses around $midval * percent(35) since * has a higher precedence than - (see this))

% is the modulus operator.

answered Mar 20, 2013 at 8:30

Déjà vu

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