How to take first number from the string in linq C# [duplicate]

Question

I need take first number from the string, for example

"12345 this is a number " => "12345"
"123 <br /> this is also numb 2" => "123"

etc.

for that I use C# code:

    string number = "";
    foreach(char c in ebayOrderId)
    {
        if (char.IsDigit(c))
        {
            number += c;
        }
        else
        {
            break;
        }
    }
    return number;

How is it possible to do same via LINQ ?

Thanks!

"some value 123 <br /> this is also numb 2" should produce 123 or error? — Ilya Ivanov
– Ilya Ivanov, Commented Mar 21, 2013 at 15:23

Justin Niessner · Accepted Answer · 2013-03-21 15:22:19Z

8

You could try Enumerable.TakeWhile:

ebayOrderId.TakeWhile(c => char.IsDigit(c));

answered Mar 21, 2013 at 15:22

Justin Niessner

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6 Comments

Ilya Ivanov Over a year ago

+1, better than regular expression

Lee Over a year ago

Note you can shorten this to ebayOrderId.TakeWhile(char.IsDigit).

joce Over a year ago

@IlyaIvanov Why is this better than a regex?

Ilya Ivanov Over a year ago

@Joce in the order of importance: readable, shorter, faster.

joce Over a year ago

@IlyaIvanov That order is quite subjective, but I get your point.

|

cuongle · Accepted Answer · 2013-03-21 15:24:10Z

2

You can use LINQ TakeWhile to get the list of digit, then new string to get the string number

var number = new string(ebayOrderId.TakeWhile(char.IsDigit).ToArray());

answered Mar 21, 2013 at 15:24

cuongle

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Comments

David · Accepted Answer · 2013-03-21 15:22:32Z

0

Use regex

Regex re=new Regex(@"\d+\w");

Try test if this works at http://derekslager.com/blog/posts/2007/09/a-better-dotnet-regular-expression-tester.ashx

Good luck!

answered Mar 21, 2013 at 15:22

David

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Comments

joce · Accepted Answer · 2013-03-21 15:49:49Z

0

I would improve on @David's answer. (\d+)[^\d]*: A number followed by anything that isn't a number.

Your number will be in the first group:

static void Main(string[] args)
{
    Regex re = new Regex(@"(\d+)[^\d]*", RegexOptions.Compiled);
    Match m = re.Match("123 <br /> this is also numb 2");

    if (m.Success)
    {
        Debug.WriteLine(m.Groups[1]);
    }
}

answered Mar 21, 2013 at 15:49

joce

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