Regular Expression in java- code error

Question

I wrote a regEx program in java. I think that is true but The result is different. please help me to fix that.

my code:

String text    ="My wife back me up over my decision to quit my job";

String patternString = "[/w/s]*back(\\s\\w+\\s)*up[/w/s]*.";

Pattern pattern = Pattern.compile(patternString, Pattern.CASE_INSENSITIVE);

Matcher matcher = pattern.matcher(text);

boolean matches = matcher.matches();

System.out.println("matches = " + matches);

output: matches = false

I'm new in java programming. I want to write a program with regEx to test match of "back up" in the input sentence.

Thanks for your attention.

I think my regEx is true but the output is false. i want to right a program for my previous question. please help me. my previous question link: stackoverflow.com/questions/15563185/… — SahelSoft
– SahelSoft, Commented Mar 23, 2013 at 7:58

Achintya Jha · Accepted Answer · 2013-03-23 08:05:09Z

3

I think you pattern should be like this:

String patternString = "[\\w\\s]*back(\\s\\w+\\s)*up[\\w\\s]*.";

answered Mar 23, 2013 at 8:05

Achintya Jha

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1 Comment

SahelSoft Over a year ago

Jho, thanks for your answer. Can you answer my question in my previous question: stackoverflow.com/questions/15563185/…

NPE · Accepted Answer · 2013-03-23 07:58:50Z

1

You are using forward slashes instead of backslashes:

String patternString = "[/w/s]*back(\\s\\w+\\s)*up[/w/s]*.";
                         ^ ^                       ^ ^

The two are not interchangeable (and don't forget that backslashes need to be doubled up).

answered Mar 23, 2013 at 7:58

NPE

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