I am working on a ' Show Online user' script where the script show everybody who is online. Now i want to remve the entry which matches the session user name i.e "if (Online user = Session User name ) then do not display it , just like on facebook.com chat where your friends id is shown and not your own Id my code is as follows :
<?php
mysql_connect("localhost","root","12345");
mysql_select_db("accounts");
$user = $_SESSION['user_name'];
$result = mysql_query("SELECT * FROM online * WHERE ($chat<>$user)");
while($row=mysql_fetch_array($result)) {
$chat=$row["emp_name"];
$chlk = ("<a href=javascript:void(0) onclick=javascript:chatWith('$chat')>$chat</a>");
$chs = ("<a>$chat</a>");
if ($chat <> $user) {
echo $chlk;
}
else {
echo $chs;
}
echo $chlk;
}
?>
I am getting the following error :
Notice: Undefined variable: chat in localhost/accounts/removeuser.php on line 7
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given localhost/accounts/removeuser.php on line 9
Any help is highly appreciated.
$resultdoes not have boolean....share code for$result