I want to output an address like this 123 Street, address, city, county, postcode
The data is stored in a database and i need to check to see if the field has anything in it so I know to output a comma in the address
$address = array($club['clubAdd1'], $club['clubAdd2'], $clubCity, $club['clubCounty'], $club['clubPostcode']);
$parts = array(
$club['clubAdd1'],
$club['clubAdd2'],
$clubCity,
$club['clubCounty'],
$club['clubPostcode'],
);
$address = array();
foreach ($parts as $part)
{
if ('' != $part)
{
$address[] = $part;
}
}
echo implode(', ', $address);
Edit: one liner
echo implode(', ', array_filter($array));
Edit 2: More accurate one liner
The problem with the above is that 0 and '0' will also be removed, which might not be desired behaviour. This will fix that:
array_filter($array, function ($value)
{
return strlen(trim($value));
}
);
a one-liner
echo implode(', ', array_filter(array($club['clubAdd1'], $club['clubAdd2'], $clubCity, $club['clubCounty'], $club['clubPostcode'])))
Running the array through the array_filter() function, without a second argument, would return an array with no empty elements.
For example:
$address_line = implode(', ',array_filter($address_array));
As Michael have noted, this would also remove nnumeric 0 values.
