Java: Assignment in Char

Question

I have a program and I need to understand it, but I don't understand two lines of it. Okay so there is one-dimensional array - int [] names, and two chars - char let1, let2. Now, there is a command:

char let1 = names[i].charAt(names[i].length()-1);
char let2 = names[i+1].charAt(0);

What does that mean?

This code wouldn't compile if names is actually an int[]. It looks pretty clear that it's a String[]. Now which specific bit of that code don't you understand? — Jon Skeet
– Jon Skeet, Commented Mar 30, 2013 at 9:41
length is an attribute if it is int[], charAt is a method and length is also a method for String. — Prateek Shukla
– Prateek Shukla, Commented Mar 30, 2013 at 9:43

David Heffernan · Accepted Answer · 2013-03-30 10:09:35Z

1

let1 is assigned the last character of names[i] and let2 is assigned the first character of names[i+1].

edited Mar 30, 2013 at 10:09

David Heffernan

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answered Mar 30, 2013 at 9:39

NPE

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Vishal K · Accepted Answer · 2013-03-30 09:52:18Z

0

char let1 = names[i].charAt(names[i].length()-1);

It means find out the string at index i of String array names and from that String extract out the character at the last index of that String. And then assign that character value to the char variable let1.

char let2 = names[i+1].charAt(0);

It means extract out the String at index i+1 from String array names and from that String extract out the character at first index (0) . And then assign that character value to the char variable let2.

edited Mar 30, 2013 at 9:52

answered Mar 30, 2013 at 9:39

Vishal K

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