javascript is not sending data through php code

Question

Hi i have a requirement where i need to execute mysql queries once user will confirm Ok from confirmation box.In my case what ever data i am passing to insert_details.php is not working. one more thing i would like to bring to your notice that i need to send data to different script and navigate it to different page.kindly suggest where is the problem?

     <script type="text/javascript">
            var r=confirm("This email address already exits in our database. Do you want to continue?");
 if (r==true)
 {  
 var dataObj = {
    fname : document.getElementById('fname').value,                  
    phone : document.getElementById('phone').value,
    pemail : document.getElementById('email').value
}
        var xhr = new XMLHttpRequest();
      xhr.open("POST","insert_details.php", true);
      xhr.setRequestHeader('Content-Type', 'application/json; charset=UTF-8');
      xhr.send(JSON.stringify(dataObj));

xhr.onreadystatechange = function() {
    if (xhr.readyState>3) {
        window.location = 'http://localhost/myproject/test.php?eid=<?php echo $primary_email; ?>';
    }
}

alert("test");



  }
else
  {
   window.location = 'http://localhost/myproject/registration_request.php'
   }

    </script>

code in insert_details.php

$date = "Date:" . date("d/m/Y h:i:s") . "\n"; //to get today's date and time                  
        $logfile = "testing";
         $fpath ="myproject/";
        $filepath = $fpath .$logfile . '-log-' . date('Y-m-d') . '.csv';  //path of error log file

        $fh1 = fopen($filepath, 'a') or die("can't open file"); //opening the error log file 
        fwrite($fh1, "******************index*******************" . "\n");
        fwrite($fh1, $date); 


$test=json_decode(file_get_contents('php://input'));
fwrite($fh1, $test[0]);

How are you accessing it in PHP? Since you're using JSON data, you can't use $_POST variables inside PHP. You'd have to use json_decode(file_get_contents('php://input')); — Colin M
– Colin M, Commented Apr 1, 2013 at 12:53
yeah i am using the same line of code in insert_details.php page. but it is not working — Ethen
– Ethen, Commented Apr 1, 2013 at 12:59
"it is not working" is an extremely vague description. What happens when you var_dump(file_get_contents('php://input'));? — Colin M
– Colin M, Commented Apr 1, 2013 at 13:03
Sorry Colin. i put it as //$str_json = file_get_contents('php://input'); then i am trying to this $email = json_decode($_POST['pemail']); mysql_query("UPDATE P_P SET First_Name='$fname', Updated_By='user',Updated_Date=Now() WHERE Email_Address_Primary='$email'"); is it fine? — Ethen
– Ethen, Commented Apr 1, 2013 at 13:10
No, not fine. By posting the data as JSON, you can no longer use $_POST. $_POST is auto-parsed by PHP when PHP sees an incoming request with an application/x-www-form-urlencoded or multipart/form-data value for the Content-Type header. Follow up with epascarello below — Colin M
– Colin M, Commented Apr 1, 2013 at 13:12

epascarello · Accepted Answer · 2013-04-01 13:56:56Z

2

You are not sending up a named pair. You are just sending up the value of the textbox.

what is looks like as a string.

xhr.send("[email protected]");

Second you have a race condition between the Ajax call and the window.location.href.

You need to wait for the response to come back before doing the redirection.

Basic idea:

var dataObj = {
    fname : document.getElementById('fname').value,                  
    phone : document.getElementById('phone').value,
    pemail : document.getElementById('email').value
}
xhr.onreadystatechange = function() {
    if (xhr.readyState>=3) {
        window.location = 'http://localhost/myproject/test.php?eid=<?php echo $primary_email; ?>';
    }
}
xhr.send(JSON.stringify(dataObj));

edited Apr 1, 2013 at 13:56

answered Apr 1, 2013 at 13:03

epascarello

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11 Comments

Colin M Over a year ago

If he's using json_decode with php://input the named-pair theory should be a non-issue. But hah, I didn't even pay attention to the window.location assignment.

Ethen Over a year ago

Then what should be the proper way of doing this?How to send it as named pair? i am novice in this. kindly help.

Ethen Over a year ago

Thank you Epascarello. do i need to use this also xhr.open("POST","insert_details.php", true); where i need to send dataObj?

epascarello Over a year ago

Yes, you still need all of that, I just put in the code that needed to change.

Ethen Over a year ago

Still it is not working:( i have reposted my code in my question. it is neither going to insert_details.php nor to test.php page

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