I am using the following as an example posted on the php manual that should let me use the return value of a method call inside a string...
echo "This is the value of the var named by the return value of getName(): {${getName()}}";
function getName()
{
return "Bob";
}
However I get an error: "Notice: Undefined variable: Bob"
This example is from the php manual here: http://php.net/manual/en/language.types.string.php
Is the manual wrong or am i doing something wrong here?
You now have this:
"... {$getName()}"
This means that PHP is running the getName() function, gets Bob back and then reads:
"... {$Bob}"
Now, he is trying to get the variable $Bob (because variables are parsed in double quotes).
The solution is to use single quotes and put the function call outside the string:
'... {$'.getName().'}'
Or escape it:
"... \{\$getName()\}"
$x = 'getName'; echo "{$x()}";. Not that I recommend using them, but they do come in handy on occasion.
x() and then $<return-value-of-x>echo "{getName()}" will not work - it only works on variable expansion.You could do it like this and it should do what you inteded
echo "This is the value of the var named by the return value of ".getName();
function getName()
{
return "Bob";
}
Hope this is helping you
