Javascript calling function inside function

Question

I am trying to get the function in a function with argument inside the child function

function firstF (){
  this.childF1 = function($argument){
    // do something + $argument
  }
  this.childF2 = function($argument2){
    // do something + $argument2
  }
}

//Declare a new firstF
var firstFunction = new firstF();
firstFunction.childF1

how do i declare the $argument here?

I strongly recommend you to read developer.mozilla.org/en-US/docs/JavaScript/… — plalx
– plalx, Commented Apr 2, 2013 at 2:52

jfriend00 · Accepted Answer · 2013-04-02 02:50:28Z

2

You do it like this:

var firstFunction = new firstF();
firstFunction.childF1(arghere)

childF1 is a property of your firstF object and that property is a function. So, you call it like a function with parens and you pass the arguments in the parens. You must call it on an already created object of type firstF, not on the firstF function itself.

answered Apr 2, 2013 at 2:50

jfriend00

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