I am working on BitWise AND operator in javascript.
I have two 32 bit nunber
4294901760 (11111111 11111111 00000000 00000000) and
4294967040 (11111111 11111111 11111111 00000000)
when I and them bitwise 4294901760 & 4294967040 I got -65536 as a result although the result should be 4294901760.
Can any one please guide me am I missing something? Or what is the correct way to do it. Thanks
console.log((4294901760 & 4294967040) >>> 0);
Append >>> 0 to have it interpret your operation as unsigned.
Fiddle:
http://jsfiddle.net/JamZw/
More info:
Bitwise operations on 32-bit unsigned ints?
Operands of bitwise operations in javascript are converted to signed 32 bit integers. Unsigned 4294901760 has same binary representation as signed -65536.
You can use >>> 0 to convert result of & to unsigned, eg:
(4294901760 & 4294967040) >>> 0
Check this custom implementation of AND bitwise operation:
function and(a, b){
a = a.toString(2).split('');
b = b.toString(2).split('');
var length = Math.max(a.length, b.length);
function padZeroes(array, size){
while(array.length <= size ){
array.unshift('0');
}
}
padZeroes(a, length);
padZeroes(b, length);
var result = [];
$.each(a, function(i, v){
result.push((a[i]==b[i] && a[i]!='0')?'1':'0');
});
var r = parseInt(result.join(''), '2');
return r;
}
&operation?