picking random in python

Question

I am new to python, so I apologise if the answer is obvious.

I am trying to pick 10 random numbers from a range of 128 numbers. And then if a certain number is present in this list, then print the (list) or a (word) or something.

I can pick the 10 random numbers and print these random numbers, but I am having trouble printing if a number is present in this random list.

I am picking and printing the 10 random numbers in the following way:

import random
list = random.sample(range(128), 10)
print list

I am trying to print (something), if a number in this case 5, is present in this random list in the following way:

import random
list = random.sample(range(128), 10)
if list == 5:
    print list

@Kos -- Yeah -- I was debating whether I should fix that syntax error or not ... — mgilson
– mgilson, Commented Apr 4, 2013 at 13:07
@mgilson I did since no initial whitespace at all was present; go ahead and rollback if you find my edit invalid — Kos
– Kos, Commented Apr 4, 2013 at 13:09
@Kos -- Nah, probably not worth it here. If it ends up being an issue OP'll let us know. — mgilson
– mgilson, Commented Apr 4, 2013 at 13:10

Kos · Accepted Answer · 2013-04-04 13:06:26Z

3

Use the in operator: if 5 in list

Also list is the name of the type, so I suggest to use another name for the variable.

answered Apr 4, 2013 at 13:06

Kos

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Comments

tanaydin · Accepted Answer · 2013-04-04 13:26:16Z

0

you can make it like this.

if 5 in list:
    print list

edited Apr 4, 2013 at 13:26

answered Apr 4, 2013 at 13:09

tanaydin

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1 Comment

Mark Over a year ago

Thanks for your help, I tried this but I am getting an error that says: SyntaxError:invalid syntax

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