Started learning Javascript and I wrote something like this in FireBug of FireFox:
var myObject = {
"first_name" : "Rick",
"last_name" : "Hummer"
};
var name;
for (name in myObject) {
if(typeof myObject[name] != 'function') {
(name + ' : ' + myObject[name])
}
}
When I run it, it only shows the last name, shouldn't it also list first name ?
Plus how can I put break points and debug this anyway?
You didn't tell the browser to output the values.
By default it writes out the result of the last executed line which is (name + ' : ' + myObject[name])
To solve this simply add console.log:
var myObject = {
"first_name" : "Rick",
"last_name" : "Hummer"
};
var name;
for (name in myObject) {
if(typeof myObject[name] != 'function') {
console.log(name + ' : ' + myObject[name]);
}
}
Works for Firefox 19:
You have a statement that doesn't do anything, it builds a string but doesn't use it. The debugger is probably just showing you the last statement that was executed.
Change
(name + ' : ' + myObject[name])
To:
console.log(name + ' : ' + myObject[name])
and you should see both keys appear in the log.
Also, for debugging, you should simply write 'debugger' (without any quotes) at the line you want to put a breakpoint. As I know all browsers support that statement.
