I'm trying to get a random integer within a range by reading from crypto.randomBytes().
Now, my problem is that I do not know how to read integers from that byte stream. I imagine generating a range is simply a matter of 'throwing away' the ints not in range.
Any ideas?
You can get one 32 bit integer from crypto.randomBytes with the code below. If you need more than one you can ask for more bytes from crypto.randomBytes and then use substr to individually select and convert each integer.
crypto.randomBytes(4, function(ex, buf) {
var hex = buf.toString('hex');
var myInt32 = parseInt(hex, 16);
});
Having said that, you might want to just use Math.floor(Math.random() * maxInteger)
To obtain a cryptographically secure and uniformly distributed value in the [0,1) interval (i.e. same as Math.random()) in NodeJS
const random = crypto.randomBytes(4).readUInt32LE() / 0x100000000;
console.log(random); //e.g. 0.9002735135145485
or in the Browser
const random = window.crypto.getRandomValues(new Uint32Array(1))[0] / 0x100000000;
console.log(random);
const { randomInt } = await import('crypto');
const n = randomInt(1, 7);
console.log(`The dice rolled: ${n}`);
Now it is implemented in node itself https://nodejs.org/api/crypto.html#crypto_crypto_randomint_min_max_callback
