take two arrays and make a third array from values that are NOT unique

Question

I'm attempting to de-dupe an enormous email list migration, however there's a catch. I'd like to take the duplicates and turn them into their own array (3rd).

Lets make these arrays very simple, and short.

a = ["[email protected]", "[email protected]"]
b = ["[email protected]"]

Essentially i'm trying to make c = ["[email protected]"] because it's the only email that resides on both lists.

What I've attempted so far:

Is there an opposite to unqiq ?

ab = a + b
ab.uniq

returns: ["[email protected]", "[email protected]"]

Could I dump a + b into a third c array, and compare c to ab.uniq to get what's duplicated?

Am i missing an easier way to do this? Any help will be much appreciated!!!!

Intelekshual · Accepted Answer · 2013-04-09 22:49:46Z

6

You want the intersection of the arrays.

c = a & b

edited Apr 9, 2013 at 22:49

answered Apr 9, 2013 at 21:50

Intelekshual

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2 Comments

jahrichie Over a year ago

Is there a way to turn a list with carriage returns into an array of strings? ["on]

Intelekshual Over a year ago

Is the list a string, or an array? If it's a string, you can use String#split: "some string with carriage returns".split(/\r?\n/)

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