How can I traverse (read all the nodes in order) a XML document using recursive functions in c#?
What I want is to read all the nodes in xml (which has attributes) and print them in the same structure as xml (but without Node Localname)
Thanks
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1I still don't understand what you really want to do. Can you maybe show a very simple and short example? What does your original XML look like, what do you want back? What do you mean by "print them" - write to the console? Write to a file? And shouldn't you be looking at XSLT for converting from XML to XML? Seems like a perfect fit.marc_s– marc_s2009-10-20 18:26:48 +00:00Commented Oct 20, 2009 at 18:26
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I agree XSLT is the best 1..but here i expected a simple recursive algo..thnx anywayKaja– Kaja2009-10-25 15:57:21 +00:00Commented Oct 25, 2009 at 15:57
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3 Answers
using System.Xml;
namespace ConsoleApplication1
{
class Program
{
static void Main( string[] args )
{
var doc = new XmlDocument();
// Load xml document.
TraverseNodes( doc.ChildNodes );
}
private static void TraverseNodes( XmlNodeList nodes )
{
foreach( XmlNode node in nodes )
{
// Do something with the node.
TraverseNodes( node.ChildNodes );
}
}
}
}
1 Comment
Josh Close
If this solved your problem, can you mark it as the correct answer? Thanks.
IEnumerable<atype> yourfunction(XElement element)
{
foreach(var node in element.Nodes)
{
yield return yourfunction(node);
}
//do some stuff
}
4 Comments
Kaja
i think my question in not giving enough explanation.What i want is, want to read all the nodes in xml(which has attributes) and print it in the same structure as xml(but without Node Localname)
bmm6o
the return prevents the loop from, er, looping.
Seb
@bmm6o : have a look at the "yield return" instruction : msdn.microsoft.com/en-us/library/9k7k7cf0.aspx
Gregoire
@Seb: it my fault, I had forgotten the yield before :)
static void Main(string[] args)
{
XmlDocument doc = new XmlDocument();
doc.Load("../../Employees.xml");
XmlNode root = doc.SelectSingleNode("*");
ReadXML(root);
}
private static void ReadXML(XmlNode root)
{
if (root is XmlElement)
{
DoWork(root);
if (root.HasChildNodes)
ReadXML(root.FirstChild);
if (root.NextSibling != null)
ReadXML(root.NextSibling);
}
else if (root is XmlText)
{}
else if (root is XmlComment)
{}
}
private static void DoWork(XmlNode node)
{
if (node.Attributes["Code"] != null)
if(node.Name == "project" && node.Attributes["Code"].Value == "Orlando")
Console.WriteLine(node.ParentNode.ParentNode.Attributes["Name"].Value);
}
