Unable to open file to array in C++

Question

I am trying to open a file and read the contents into a couple arrays. I can't find what I am doing wrong. I am using the absolute path. The input file looks something like this:

Sam     100    23   210
Bob     1     2    12
Ted     300   300   100
Bill    223   300   221
James   234   123   212
Luke    123   222   111
Seth    1     2     3
Tim     222   300   180
Dan     222   111   211
Ben     100   100     2

Here is my code:

#include "stdafx.h"
#include <fstream>
#include <iostream>
#include <string>

using namespace std;

int main()
{
string name;
ifstream inFile;
string bowlerNames[10];
int bowlerScores[10][3] = {0};


inFile.open("C:\\Users\Seth\Documents\bowlingData.txt");

if (inFile.is_open()) //Checking if the file can be opened
{

for (int i = 0; i < 10; i++)
{
    inFile  >> bowlerNames[i] 
            >> bowlerScores[i][0]
            >> bowlerScores[i][1]
            >> bowlerScores[i][2];
}

for (int i = 0; i < 10; i++)
{
    cout    << bowlerNames[i] 
            << bowlerScores[i][0]
            << bowlerScores[i][1]
            << bowlerScores[i][2];
}
}
else cout << "Unable to open file..." <<endl; //Gives that sentence if the file can't be opened

inFile.close();

cout << endl; //spacing
system("Pause");
return 0;
}

The output before I fixed the backslash problem (Thx Floris) was "unable to open file" :) — setherj
– setherj, Commented Apr 12, 2013 at 23:02

Floris · Accepted Answer · 2013-04-12 23:05:04Z

2

All the backslashes have to be double backslash!

inFile.open("C:\\Users\\Seth\\Documents\\bowlingData.txt");

Confirm this for yourself by doing something like this:

string fileName = "C:\\Users\\Seth\\Documents\\bowlingData.txt");
cout << fileName << endl;

edited Apr 12, 2013 at 23:05

answered Apr 12, 2013 at 22:58

Floris

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4 Comments

setherj Over a year ago

That seems like it will work. But why wouldn't it open when I just had the file name in there (with no backslashes). I had both the files in the same directory to my knowledge.

Floris Over a year ago

I can't answer the question "why didn't it open when I used a relative path" - not enough information, sorry. Glad that it worked like this, though.

setherj Over a year ago

I had inFile.open("bowlingData.txt"); but yet it was not opening, even when they were in the same directory.

Floris Over a year ago

To start, I would look at this answer and use the method given there to confirm you are indeed starting from the directory you think you're starting from... There is more helpful information in the answers to this question. Hope that helps.

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