converting a const char to an array

Question

I am trying to convert a const char, to a char... here is my code:

bool check(const char* word)
{

char *temp[1][50];

temp = word;

return true;
}

It is a function with a const char passed in. I need to convert that const char to a char. When I run this code now, the compiler throws up this error:

dictionary.c:28:6: error: array type 'char *[1][50]' is not assignable
temp = word;

How do I correctly complete this conversion?

Thanks, Josh

Notinlist · Accepted Answer · 2013-04-13 16:15:40Z

6

#include <string.h>
bool check(const char* word)
{
    char temp[51];
    if(strlen(word)>50)
        return false;
    strncpy(temp,word,51);
    // Do seomething with temp here
    return true;
}

answered Apr 13, 2013 at 16:15

Notinlist

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2 Comments

Joshua McDonald Over a year ago

ok, great that works, now I need to implement the next part of the program, which is checking if the word stored in temp is a correctly spelled word in the dictionary... To do this I have a global variable that holds the dictionary. Here is the code that defines it, so you know what I am working with: char *result = NULL; I need to be able to tell if somewhere in "result" there is a string = to temp. It then needs to return true if an identical string is found (meaning the word is spelled correctly) and false otherwise. If you can also help me with this I would greatly appreciate it!

luizfls Over a year ago

@JoshuaMcDonald you should ask a new question.

James M · Accepted Answer · 2013-04-13 16:15:53Z

1

If you want a non-const version, you'll have to copy the string:

char temp[strlen(word) + 1];
strcpy(temp, word);

Or:

char * temp = strdup(word);

if(!temp)
{
    /* copy failed */

    return false;
}

/* use temp */

free(temp);

answered Apr 13, 2013 at 16:15

James M

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