creating a value for the css method

Question

This doesn't work. I don't understand why this won't work. $tops turns into combined then that value is used to give css top value

var $popout = $('.popOut'),
      $currentButton,
      $win = $(window),
      $trigger = $('#leaderBottom a'),
      $closeOut = $('.xOut');





$('#leaderBottom a').on("click", function(event) {
      event.preventDefault();
        $popout.css('display','block');
        $('<div class="overlay"></div>').appendTo('#leaderBottom');

          // find the position of the link according to window
           var $tops = $(this).offset();

          // combined  that nuM plus 50
           var combin = $tops + 50;

            ///adds it all up. and it sends it to combined
           $popout.css("top",combin);

           console.log(combin);



  });

i think you have to say something like $popout.css("top","12px");, px should be in there. — 1337holiday
– 1337holiday, Commented Apr 14, 2013 at 19:25

user835223 · Accepted Answer · 2013-04-14 19:24:18Z

1

jQuery offset() returns an object which contains the co-ordinates. So you would want to do:

var combin = $tops.top + 50;

answered Apr 14, 2013 at 19:24

user835223

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