unix Syntax error near unexpected token 'done'

Question

This script

#!/bin/sh
once=true

while $once do
stop & PID=$!
sleep 10M

if [$!=0]; then
start
break
else
kill $PID
fi

done

Gives

./restart.sh: line 18: syntax error near unexpected token `done'
./restart.sh: line 18: `done'

I don't understand, it had run previously on another unix system. Am i missing something?

EDIT

stop and start are functions that simply run stop.sh and start.sh respectively.

devnull · Accepted Answer · 2013-04-15 08:00:31Z

4

You seem to be missing a semicolon on line 4. Modifying it to read

while ${once}; do

should fix it.

answered Apr 15, 2013 at 8:00

devnull

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