Addition on three dimensional array

Question

I'm trying to understand multidimensional arrays I added some integer values randomly iam having a problem finding the sum of two random integers as the third dimension something like this

      Random  val=new Random();

    int [][][]myloop=new int[2][2][2];
    for (int i = 0; i < myloop.length; i++) {

        for (int j = 0; j < myloop[0].length; j++) {
            for (int k = 0; k < 2; k++) {

                myloop[i][j]=val.nextInt();
            }

        }



    }

NeplatnyUdaj · Accepted Answer · 2013-04-16 20:14:53Z

6

You didn't add random values. You initialized an array of random dimensions.

This is probably the code you're looking for(based on the discussion below):

Random val = new Random();
int numberOfPairs=10; //example
int[][] data = new int[numberOfPairs][3];
for (int i=0;i<numberOfPairs;i++){
    data[i][0]=val.nextInt();
    data[i][1]=val.nextInt();
    data[i][2]=data[i][0]+data[i][1];
}

edited Apr 16, 2013 at 20:14

answered Apr 16, 2013 at 19:38

NeplatnyUdaj

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3 Comments

NeplatnyUdaj Over a year ago

But I still don't have any idea if the question is wrong or the code below is wrong. Could you try to rephrase the question to make it more clear or add some information. What should be the output?

digrev Over a year ago

Sure.I have three dimensional array .First dimension is for first integer value.Second is for second integer value .Finally, third dimension is for sum of these two values.I tried something like this but i cant figured out how can i do this

NeplatnyUdaj Over a year ago

So the problem is that you don't understand the basic data structures(do some googling on arrays). You don't need a three-dimensional array. You need two dimensional array[n][3], where n is the number of tuples.

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