How to Declare byte* ( byte array ) in c++ and how to define as a parameter in function definition?
when I declare like below
Function Declaration:
int Analysis(byte* InputImage,int nHeight,int nWidth);
Getting error : "byte" undefined
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use unsigned char instead. its the same....one bytesomeone_ smiley– someone_ smiley2013-04-18 09:49:21 +00:00Commented Apr 18, 2013 at 9:49
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then how should i convert byte* in to unsigned char, getting byte array input from the C# application.Pixel– Pixel2013-04-18 09:53:48 +00:00Commented Apr 18, 2013 at 9:53
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Did you want to convert byte from c# to char in c++? am i understand this correctly?someone_ smiley– someone_ smiley2013-04-18 10:02:28 +00:00Commented Apr 18, 2013 at 10:02
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1I think you can do this by convert byte into char in c# before pass on to c++ charsomeone_ smiley– someone_ smiley2013-04-18 10:03:29 +00:00Commented Apr 18, 2013 at 10:03
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This one should help you in converting byte in c# to char stackoverflow.com/questions/5431004/…someone_ smiley– someone_ smiley2013-04-18 10:04:54 +00:00Commented Apr 18, 2013 at 10:04
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2 Answers
There is no type byte in C++. You should use typedef before. Something like
typedef std::uint8_t byte;
in C++11, or
typedef unsigned char byte;
in C++03.
Comments
The C++ type representing a byte is unsigned char (or other sign flavour of char, but if you want it as plain bytes, unsigned is probably what you're after).
However, in modern C++, you shouldn't be using raw arrays. Use std::vector<unsigned char> if your array is runtime-size, or std::array<unsigned char, N> (C++11) if your array is of static size N. You can pass these to functions via (const) references, like this:
int Analysis(std::vector<unsigned char> &InputImage, int nHeight, int nWidth);
If Analysis does not modify the array or its elements, do this instead:
int Analysis(const std::vector<unsigned char> &InputImage, int nHeight, int nWidth);
answered Apr 18, 2013 at 9:49
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