Can I use Parameters of a method invoked within an array in Java

Question

This is in the main() method:

Movie[] list = new Movie[6];

list[0] = new Animated(.25, 700.000, "Mulan", "Barry Cook", 1998, 15.000);
list[1] = new Animated(.23, 45.000, "TMNT", "Steve Barron", 1990, 12.000);
list[2] = new Documentary(12, 7.000, "Nixon", "Oliver Stone", 1995, 50.000);
list[3] = new Documentary(10, 4.500, "JFK", "Oliver Stone", 1991, 35.000);
list[4] = new Drama(3.500, 8.25, "Belly", "Hype Williams", 1998, 20.000);
list[5] = new Drama(4.500, 9.00, "42", "Brian Helgeland", 2013, 16.000);

System.out.print(menu());
System.out.print("Select and menu option 1-5: ");
choice = input.nextInt();
do
{
    switch(choice)
    {
        case 1: movieList(list);
        break;

and I'm calling the movieList(list) method which exists within the class outside main:

public static void movieList(Movie[] a)
{
    System.out.printf("\n\n%-10s %-10s %-10s %-10s %-10s", "TITLE", "YEAR",
    "REVENUE", "PROFIT", "CATEGORY");
    System.out.printf("\n\n%-10s", Movie[0].getTitle());
}

This is the method I am calling in case 1, how I have been trying to use one Parameter and I get "cannot find symbol" error with the pointer at Movie. I have been searching and I am beginning to think I cannot access this value this way.

NilsH · Accepted Answer · 2013-04-20 05:41:06Z

4

The name of your Movie[] parameter in your movieList method is a, so try using a[0].getTitle() instead of Movie[0].getTitle(). Parameters in a method are always accessed by it's name, not it's type.

answered Apr 20, 2013 at 5:41

NilsH

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