php loop through json array

Question

I have a json string like this:

$fields_string = '
{"fields":
   {"customers":[{"name":"john","id":"d1"},
                 {"name":"mike","id":"d2"},
                 {"name":"andrew","id":"d3"},
                 {"name":"peter","id":"d4"}]
   }
}'

How can I print each name? I will use them later in a html select options, I know how to do that. But I couldn't get the string out. Here are something I tried:

$obj = json_decode($fields_string);
$fields_detail = $obj-?{"fields"}->{"customers"};

at this point, I am able to print the customer array out by echo json_encode($fields_detail), but before that, I want to get the name break down using foreach. I tried several times, it didn't work. Can anyone help please.

Thanks!

You want to get what? How did you try? How did it not work?

Jon
– Jon

2013-02-21 11:18:40 +00:00
Commented Feb 21, 2013 at 11:18 — Jon
– Jon, Commented Feb 21, 2013 at 11:18

Maks3w · Accepted Answer · 2013-02-21 11:19:19Z

5

Customers is an array of objects so iterating over each object and reading the property should work.

foreach ($fields_detail as $customer) {
  echo $customer->name;
}

answered Feb 21, 2013 at 11:19

Maks3w

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2 Comments

Maks3w Over a year ago

@koopajah you missed the second fragment of code phpfiddle.org/lite/code/xr4-8tz

the_summer_bee Over a year ago

I see what I have done wrong. This is just it. Thank you very much!

Jan Hančič · Accepted Answer · 2013-02-21 11:21:04Z

3

Something like this:

$data = json_decode($fields_string, true); // return array not object
foreach($data['fields']['customers'] as $key => $customer) {
 echo $customer['name']; 
}

answered Feb 21, 2013 at 11:21

Jan Hančič

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Comments

MrCode · Accepted Answer · 2013-02-21 11:29:25Z

2

Access the names via fields->customers:

$obj = json_decode($fields_string);

foreach($obj->fields->customers as $customer)
{
    echo $customer->name . "\n";
}

Demo

answered Feb 21, 2013 at 11:29

MrCode

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Comments

sanj · Accepted Answer · 2013-02-21 11:23:05Z

0

foreach($obj->fields->customers as $fields)
echo $fields->name;

answered Feb 21, 2013 at 11:23

sanj

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