foreach loop in expect script not accepting variables

Question

#!/bin/bash
expect << EOF
exp_internal 1

spawn ssh [email protected]
expect "ssword:"
send "********\r"
sleep 3
set list [open list1 r]

foreach line \$list 
{
   expect " $"
   send "seeisso \$list | grep -E -i ' os |proddropdown|hostname'"
   send "\r"
   sleep 5
   expect -re " $"
   set fid [open out1.txt a]
   puts \$fid \$expect_out(buffer)
}
close $fid

EOF

======

List 1 contains:

APSE0112

ETLLT0000

=============

result of the script:

expect: does " " (spawn_id exp6) match glob pattern " $"? yes
expect: set expect_out(0,string) " "
expect: set expect_out(spawn_id) "exp6"
expect: set expect_out(buffer) " "
send: sending "seeisso file7 | grep -E -i ' os |proddropdown|hostname'" to { exp6 }
send: sending "\r" to { exp6 }

expect: does "" (spawn_id exp6) match regular expression " $"? no


expect: does "\r\n" (spawn_id exp6) match regular expression " $"? no
seeisso file7 | grep -E -i ' os |proddropdown|hostname'

expect: does "\r\nseeisso file7 | grep -E -i ' os |proddropdown|hostname'\r\n" (spawn_id exp6) match regular expression " $"? no

===================

I don't know from where it is taking file7 value. and when i change:

send "seeisso \$list | grep -E -i ' os |proddropdown|hostname'"

to

send "seeisso **$list** | grep -E -i ' os |proddropdown|hostname'"

it takes an empty value:

expect: set expect_out(0,string) " "
expect: set expect_out(spawn_id) "exp6"
expect: set expect_out(buffer) " "

send: sending "seeisso  | grep -E -i ' os |proddropdown|hostname'" to { exp6 }
send: sending "\r" to { exp6 }

expect: does "" (spawn_id exp6) match regular expression " $"? no


expect: does "\r\n" (spawn_id exp6) match regular expression " $"? no
seeisso  | grep -E -i ' os |proddropdown|hostname'

===========

Please help

Why do you have a backslash before $list, (i.e. \$list)? Also, I don't see your use of the line variable. — Hai Vu
– Hai Vu, Commented Apr 24, 2013 at 16:46
In a bash here-doc, if you single-quote the here-doc terminator, you effectively single-quote the whole thing. That would alleviate much of your escaping. However, the entire bash script is effectively an expect program. Do away with bash altogether. Change the she-bang line to: #!/usr/bin/expect -f. — glenn jackman
– glenn jackman, Commented Apr 25, 2013 at 21:02
A Tcl error: commands are terminated by semicolons and newlines, so you must place the opening brace on the same line as the foreach command. — glenn jackman
– glenn jackman, Commented Apr 25, 2013 at 21:02

Hai Vu · Accepted Answer · 2013-04-24 16:52:40Z

2

I saw a couple of problems:

list in your case is really a file handle, not the contents of the file.
You have backslash before $list, which I don't understand the reason
You don't use your line variable

Here is a suggestion to see if it works:

set fileHandle [open list1]
while {[gets $fileHandle line] != -1} {
    expect " $"
    send "seeisso $line | grep -E -i ' os |proddropdown|hostname'"
    send "\r"
    # the rest ...
}
close $fileHandle

answered Apr 24, 2013 at 16:52

Hai Vu

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2 Comments

nis Over a year ago

I tried your code and got following error:send: sending "password\r" to { exp6 } can not find channel named "line" while executing "gets line"

nis Over a year ago

I tried your code using expect(not in bash) and it worked thanks. Not sure why it was not working with bash script.

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