Adding days to date in php

Question

I read about this but does not working for me. Here is my code:

$today = date_create()->format("d/m/Y"); // Today is 25/04/2013
$num_days = GetNumberOfdays();
$end_date = date("d/m/Y", strtotime($today . " + $num_days days"));

The value that I get from $end_date is 31/12/1969. What am I doing wrong?

It looks like your strtotime string needs to be reversed. php.net/manual/en/datetime.formats.relative.php — Schleis
– Schleis, Commented Apr 25, 2013 at 14:13

Unexpected Pair of Colons · Accepted Answer · 2013-04-25 14:31:33Z

2

Try this instead:

$end_date = date("d/m/Y", strtotime("+ $num_days days", time()));

EDIT: I changed the $today variable to just time() which is essentially getting you the same information if you're just looking for today's date.

edited Apr 25, 2013 at 14:31

answered Apr 25, 2013 at 14:14

Unexpected Pair of Colons

7691 gold badge7 silver badges19 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Unexpected Pair of Colons Over a year ago

@Overflow012 I updated my answer. Try that out and see if it works for you.

Cristhian Boujon Over a year ago

I checked it with var_dump() And I get an int so it is ok.

SubjectCurio · Accepted Answer · 2013-04-25 14:13:56Z

1

From what it looks like you're trying to do, you don't even need $today (as it defaults to now if date is not supplied), so you could just do eg:

 $end_date = date("d/m/Y", strtotime("+ 5 days")); 
 echo $end_date;

result would be

 30/04/2013

if you want to provide a date, you need the parameters the other way round, as per the manual:

strtotime ( string $time [, int $now = time() ] )

answered Apr 25, 2013 at 14:13

SubjectCurio

4,9103 gold badges34 silver badges48 bronze badges

Comments

xdazz · Accepted Answer · 2013-04-25 14:15:28Z

1

date_create() return a DateTime object.

You could use DateTime::modify method.

answered Apr 25, 2013 at 14:15

xdazz

161k38 gold badges255 silver badges278 bronze badges

Comments

Mark Baker · Accepted Answer · 2013-04-25 14:24:35Z

1

$date = new \DateTime(); // Defaults to Today
$num_days = 123;
$date->add(
    new \DateInterval('P' . $num_days . 'D')
);
echo $date->format('d-M-Y');

answered Apr 25, 2013 at 14:24

Mark Baker

213k34 gold badges354 silver badges390 bronze badges

Comments

zkanoca · Accepted Answer · 2013-04-25 14:16:18Z

0

$today = date_create()->format("d/m/Y"); // Today is 25/04/2013

$num_days = date_create()->format("d");

echo $end_date = date("d/m/Y", strtotime(" + $num_days days"));

answered Apr 25, 2013 at 14:16

zkanoca

10k10 gold badges55 silver badges99 bronze badges

Comments

Chrysus · Accepted Answer · 2013-04-25 14:24:38Z

0

<?
// note change of $today format
$today = date_create()->format("d-m-Y"); // Today is 25-04-2013
$num_days = GetNumberOfdays();
$end_date = date("d/m/Y", strtotime("+" . $num_days . " days", strtotime($today)));
?>

answered Apr 25, 2013 at 14:24

Chrysus

3591 silver badge6 bronze badges

Collectives™ on Stack Overflow

Adding days to date in php

6 Answers 6

2 Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

2 Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related