Php function from a variable

Question

I want to be able to submit a value from a form and then call the function submitted, my code:

<?php
include 'specs.php';
if (empty($_POST) === false) {
$func = $_POST['function'];
$a1 = $_POST['a1'];
$a2 = $_POST['a2'];
$a3 = $_POST['a3'];
$a4 = $_POST['a4'];
$a5 = $_POST['a5'];
echo $func.'('$a1', '$a2', '$a3', '$a4', '$a5');';
}
?>
<form action="" method="post">
Function:<br><input type="text" name="function"><hr>
Value 1: <input type="text" name="a1">
Value 2: <input type="text" name="a2">
Value 3: <input type="text" name="a3">
Value 4: <input type="text" name="a4">
Value 5: <input type="text" name="a5">
<input type="submit" value="Execute">

Hopefully that's behind some kind of login or you whitelist the allowed function calls. — mario
– mario, Commented Apr 26, 2013 at 2:18

What have you tried · Accepted Answer · 2013-04-26 02:22:43Z

4

You can use call_user_func_array

call_user_func_array ( 'thefuncname' , your_parameters )

In your case it would be something like:

$func = $_POST['function'];
$parameters = array($a1, $a2, $a3, $a4, $a5);
call_user_func_array ( $func, $pameters);

edited Apr 26, 2013 at 2:22

answered Apr 26, 2013 at 2:16

What have you tried

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Comments

Shomz · Accepted Answer · 2013-04-26 02:19:30Z

1

Or just echo $func(array($a1, $a2, $a3, $a4, $a5));

(maybe you don't want an array, so you can just put $func($a1, $a2, $a3, etc);)

answered Apr 26, 2013 at 2:19

Shomz

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raidenace · Accepted Answer · 2013-04-26 02:18:43Z

0

replace

echo $func.'('$a1', '$a2', '$a3', '$a4', '$a5');';

with

call_user_func_array($func, array($a1,$a2,$a3,$a4,$a5));

answered Apr 26, 2013 at 2:18

raidenace

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1 Comment

Shomz Over a year ago

@Evan By the looks of what OP tried to echo, seems like those are parameters indeed. Anyway, +1 for your answer.

JOE LEE · Accepted Answer · 2013-04-26 03:19:16Z

0

//suggust add some prefix on func ,then check function_exists
$func = 'auto_'.$_POST['function'];
if (function_exists( $func)) {
 $func(array($a1, $a2, $a3, $a4, $a5));
}

answered Apr 26, 2013 at 3:19

JOE LEE

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