PHP Array [$var] not working

Question

i have a simple Array and i want to call them by an $variable.

example:

$test = array(01=>"Januar",
              02=>"Februar",
              03=>"M&auml;rz",
              04=>"April",
              05=>"Mai",
              06=>"Juni",
              07=>"Juli",
              08=>"August",
              09=>"September",
              10=>"Oktober",
              11=>"November",
              12=>"Dezember");

$monat = strftime("%m",$timestamp);

So in $monat is something like "04" ... then i call my array:

echo $test[$monat];

But nothing happens ... i did not understand why ... when i call

echo $monat;

shows me "04", "03" ...

why didnt give me the array something?

When you say "nothing happens", do you mean that you get neither the array value nor an undefined index notice? Have you configured PHP to display all error messages? — Álvaro González
– Álvaro González, Commented Apr 27, 2013 at 9:45

ASGM · Accepted Answer · 2013-04-27 09:43:33Z

3

Your problem is that strftime("%m",$timestamp); returns a string (hence the str in strftime), while the keys in your array are all numbers.

If you change the keys in your arrays to be strings, then it should work:

$test = array("01"=>"Januar",
              "02"=>"Februar",
              "03"=>"M&auml;rz",
              "04"=>"April",
...

answered Apr 27, 2013 at 9:43

ASGM

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4 Comments

user2192028 Over a year ago

but strftime("%m",$timestamp); returns me 04 ... so thats equal in my array?

ASGM Over a year ago

Check the type of the returned value; it should be a string. Otherwise the leading zero wouldn't display. If you make the keys in your array strings too, then they'll match. Is that what you're asking?

Álvaro González Over a year ago

@user2192028 - If you configure your system to display error messages, PHP will tell you about these problems automatically. You'll no longer have to guess!

Emissary Over a year ago

@all could also point out for completeness - casting $monat as integer would be a reasonable alternative too... example

half-fast · Accepted Answer · 2013-04-27 09:58:11Z

0

You can make your array a little more basic, like so:

$test = array('January', 'February', 'March');

Then just add or subtract 1 depending which way you go.

ASGM has the right idea, except I would go the other way:

$test = array("January" => "04");

which can be easier to work with ... all really situational and preferential

answered Apr 27, 2013 at 9:58

half-fast

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