Sorting array of objects using the underscore sortBy method

Question

I have an array of objects and I want to sort ASC that array by the value of 'home'. That field is always numeric. So I've tried this:

_.sortBy(data.home.en, function(obj){ return obj.home });

That is working well when value of 'home' is lower then 10, but for some reason 10 goes just after the 1, so my final order looks like this 1,10,11,2,3,4,5,6,7,8,9 . Why is this happening? Thanks...

mu is too short · Accepted Answer · 2013-04-27 18:14:59Z

27

Your obj.home values are strings so they're being compared as strings and '1' < '10' is true. If you want to sort them like numbers then convert them to numbers:

_.sortBy(data.home.en, function(obj){ return +obj.home });

or:

_.sortBy(data.home.en, function(obj){ return parseInt(obj.home, 10) });

Demo: http://jsfiddle.net/ambiguous/DpfgV/1/

answered Apr 27, 2013 at 18:14

mu is too short

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6 Comments

ncubica Over a year ago

return parseInt(obj.home, 10) ==> you can do return obj.home*1 and will make the trick without using parseInt

mu is too short Over a year ago

@ncubica: I think +obj.home is the more common shortcut.

ncubica Over a year ago

but +obj.home will add string not numbers so as example if you have 10 (int) + "00" (str) result its gonna be 1000 but if you write 10 + ("00"*1) the result will be 10. which its what are you expecting right?

mu is too short Over a year ago

None of those apply here, we're just doing things like return +'10'. You're also dropping a +, the "unary plus to cast to number" version of 10 + '00'*1 would be 10 + +'00' (which requires you to be careful with your whitespace); in cases like this I'd use parseInt to make the intent crystal clear.

Tilt Over a year ago

Can't understand what the matter is about parseInt: it is clearer for readers, so why should I complicate my code using a shortcut, to save a couple of bits?

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