I'm newbie of angularjs developing and i wrote this simple app, but don't understand how i can update view, after the model il loaded from ajax request on startup!
This code don't work when I add delay into photos.php, using: sleep(3); for simulate remote server delay! instead if search.php is speedy it work!!
<!doctype html>
<html ng-app="photoApp">
<head>
<title>Photo Gallery</title>
</head>
<body>
<div ng-view></div>
<script src="../angular.min.js"></script>
<script>
'use strict';
var photos = []; //model
var photoAppModule = angular.module('photoApp', []);
photoAppModule.config(function($routeProvider) {
$routeProvider.when('/photos', {
templateUrl: 'photo-list.html',
controller: 'listCtrl' });
$routeProvider.otherwise({redirectTo: '/photos'});
})
.run(function($http) {
$http.get('photos.php')//load model with delay
.success(function(json) {
photos = json; ///THE PROBLEM HERE!! if photos.php is slow DON'T update the view!
});
})
.controller('listCtrl', function($scope) {
$scope.photos = photos;
});
</script>
</body>
</html>
output of photos.php
[{"file": "cat.jpg", "description": "my cat in my house"},
{"file": "house.jpg", "description": "my house"},
{"file": "sky.jpg", "description": "sky over my house"}]
photo-list.html
<ul>
<li ng-repeat="photo in photos ">
<a href="#/photos/{{ $index }}">
<img ng-src="images/thumb/{{photo.file}}" alt="{{photo.description}}" />
</a>
</li>
</ul>
EDIT 1, Defer solution:
.run(function($http, $q) {
var deferred = $q.defer();
$http.get('photos.php')//load model with delay
.success(function(json) {
console.log(json);
photos = json; ///THE PROBLEM!! if photos.php is slow DON'T update the view!
deferred.resolve(json);//THE SOLUTION!
});
photos = deferred.promise;
})
EDIT 2, Service solution:
...
//require angular-resource.min.js
angular.module('photoApp.service', ['ngResource']).factory('photoList', function($resource) {
var Res = $resource('photos.php', {},
{
query: {method:'GET', params:{}, isArray:true}
});
return Res;
});
var photoAppModule = angular.module('photoApp', ['photoApp.service']);
...
.run(function($http, photoList) {
photos = photoList.query();
})
...