AJAX PHP Parse URL and Content of file

Question

I have the following file: https://ajax.googleapis.com/ajax/services/search/images?v=1.0&q=mandarin

The following code: http://plnkr.co/edit/XiUOazUiIPQgN4dePXhI
Gets the images from the file and works great.

When I turn it to search the web (https://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=mandarin) I want to get the url and content "tags" from the code that's provided. Can anyone help with with my code?

Dave Chen · Accepted Answer · 2013-05-06 04:40:02Z

2

Try this:

<?php
$json=file_get_contents("http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=mandarin");
$json=json_decode($json,true);

$data=array();

foreach ($json['responseData']['results'] as $results) {
    $data[]=array("url"=>$results['url'],"content"=>$results['content']);
}

print_r($data);
?>

answered May 6, 2013 at 4:40

Dave Chen

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