Cannot use string offset as an array (What does it mean?)

Question

The code below is more or less a chunk of my code. The $servername and $monthlyincome variables are not actually static as shown here but I changed them so I could add less code here.

If I run this code...

$servername="Server1";

$months = array('January','February','March','April','May','June','July','August','September','October','November','December');


for ($i=0;$i<=24;$i++) {
    $new_time = mktime(0,0,0,date("m")+$i,1,date("Y"));
    $months_array[date("Y",$new_time)][date("m",$new_time)] = "x";
}

$overallincome = 0;

foreach ($months_array AS $year=>$month) {
    foreach ($month AS $mon=>$x) {
        $monthlyincome = 3;
        $overallincome += $monthlyincome;

        $$servername[$months[$mon-1]." ".$year]['monthlyincome']=$monthlyincome;
        $$servername[$months[$mon-1]." ".$year]['overallincome']=$overallincome;

    }
}

I get this error...

Cannot use string offset as an array in on line 123

Line 123 is this line... $$servername[$months[$mon-1]." ".$year]['monthlyincome']=$monthlyincome;

I can't figure out what I am doing wrong. I have checked other posts on SO with the same error but nothing made sense to me.

$$servername[] might be the problem. It might be interpreting it at ${$servername[]} where you want it to interpret as ${$servername}[]. Try putting those curly-brackets in there and see if that helps. — Wolfman Joe
– Wolfman Joe, Commented May 6, 2013 at 15:39
It fixed it - Thanks!!! I have a similar problem further down the code that is not exactly the same but I'm playing with it now to see if I can figure it out also. — G-J
– G-J, Commented May 6, 2013 at 15:50

Wolfman Joe · Accepted Answer · 2013-05-06 15:55:50Z

1

Putting it as an answer, then!

$$servername[] seems to be the problem. It's interpreting it as ${$servername[]} where you want it to interpret as ${$servername}[].

Try putting those curly-brackets in there and see if that helps.

edited May 6, 2013 at 15:55

answered May 6, 2013 at 15:50

Wolfman Joe

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