Setting an array as a session variable in PHP and then accessing it

Question

If I have an array:

$resultArr = pg_fetch_array($result,NULL);

and at the top of my php code I declare:

$_SESSION['resultArr'] = $resultArr;

Why can't I access the array elements like so:

for($i = 0; $i < $NUM_COLUMNS; $i++){
    // creation of the table and row are handled elsewhere.
    // The table is also within a <form> if that matters
    echo "<td>" .$_SESSION['resultArr'][$i]."</td>";
}

My table ends up having empty columns and I can't figure out why...

EDIT: I figured it out. I was declaring $_SESSION['resultArr'] = $resultArr; at the top of my code (right after session_start()) and it wasn't getting set. I moved it down to the point right after $resultArr = pg_fetch_array($result,NULL);

Is this how it's supposed to work or should it have worked fine at the top of the code?

Are you initialising the session properly? What does var_dump($_SESSION['resultArr']); output? — Mark Parnell
– Mark Parnell, Commented May 6, 2013 at 23:00
What is $NUM_COLUMNS set to? Also, are you remembering to start the session? — Graham Walters
– Graham Walters, Commented May 6, 2013 at 23:00
There is no reason this shouldn't work. Please do var_dump($_SESSION['resultArr']) to find out what's inside. — Niels Keurentjes
– Niels Keurentjes, Commented May 6, 2013 at 23:00
Well, you just answered your own question. $_SESSION['resultsArr'] is null. — Ronnie
– Ronnie, Commented May 6, 2013 at 23:18

Stefano Sanfilippo · Accepted Answer · 2013-05-06 23:05:23Z

1

Maybe you did and didn't mention, but you must call session_start() before any operation on $_SESSION

answered May 6, 2013 at 23:05

Stefano Sanfilippo

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1 Comment

Isaac Perez Over a year ago

Yep, session_start() is there at the top before anything

Neil · Accepted Answer · 2017-07-25 10:09:30Z

0

after your edit, yes this is how it is supposed to work, you first need to declare $resultArr, then put it's value in the session array

beacause in php you are no longer working with pointers, $_SESSION['resultArr'] = $resultArr; mean "$_SESSION['resultArr'] takes all the values of $resultArr at that precise moment", but it does not mean "they are thesame, if one changes, then the other changes too" .

answered Jul 25, 2017 at 10:09

Neil

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