TypeError: 'float' object is not subscriptable Python 3

Question

I keep getting TypeError: 'float' object is not subscriptable wondering why

from math import log

class Logarithm(object):

    def __init__(self, base = 0, number= 0):
        self.base = float(base)
        self.number = float(number)

        the_logarithm = log(self.base[self.number])

    def __str__(self):
        return 'Your log = {}'.format(the_logarithm)

also, it should be self.the_logarithm (both in __init__ and in __str__). — nvlass
– nvlass, Commented May 6, 2013 at 23:09

nvlass · Accepted Answer · 2013-05-06 23:12:44Z

2

Cameron Sparr's answer is correct.

You should probably re-check the help(math.log). It is

log(x[, base]) -> the logarithm of x to the given base.

meaning that the base argument is optional (defaults to e) and not log(x[base])

answered May 6, 2013 at 23:12

nvlass

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Comments

fgb · Accepted Answer · 2013-05-06 23:24:22Z

2

Because of this:

log(self.base[self.number])

What are you trying to accomplish here? self.base is a float so this statement is being evaluated as "the numberth element of base", which Python can't do.

edited May 6, 2013 at 23:24

fgb

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answered May 6, 2013 at 23:06

Cameron Sparr

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