As a beginner in python, I was trying to test the function range() in the IDLE terminal. I wrote in the terminal the below posted code and I expected to see result like this:
range(10)==>[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
But unfortunately, i do not get the expected result
Python Code I Tried:
range(10)
print(range(10))
The Result From The shell:
range(10)
In python 3, range() returns a generator, that's why it shows you the object rather than the values:
>>> print(range(10))
range(0, 10)
If you were expecting a list, you will need to convert it to one before printing it:
>>> print(list(range(10)))
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Generators only create one value at a time in order to save memory. You can read up on them here, which includes an example suited to your test case.
C:\Documents and Settings\U009071\Desktop>python
Python 2.6.6 (r266:84297, Aug 24 2010, 18:46:32) [MSC v.1500 32 bit (Intel)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>>
>>> print(list(range(10)))
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>>
>>> for i in range(10):
... print(i)
...
0
1
2
3
4
5
6
7
8
9
>>>
>>> print(range(10))
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> print range(10)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> a = range(10)
>>> print(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Don't know your Python version, but mine works fine.
Try specifying range(0,10) to be sure.
range(0, 10) is equivalent to range(10) for any version of Python (well at least from v2.0 on and if you are using pre-2001 Python...)list is just a type defenition per se so it should work just as fine in Python2 as in Python3.
range(10)to a variable in the first line. The second lineprint(range(10))should work.range(11)?range(1, 11)?rangeis now whatxrangewas in python2. To obtain alistof numbers uselist(range(...)).