I am having a string like: "abc xyz: ID# 1000123, this is test, test 1, test 1234, "
I need to write a regular expression to extract the ID 1000123.
I have tried some thing like:
Regex betweenOfRegexCompiled = new Regex("ID# (.*), ", RegexOptions.Compiled);
But it gives "1000123, this is test, test 1, test 1234".
So, how to specify the first occurrence of the ", " ?
Instead of .* use \d+:
"ID# (\d+)"
The .* matches any number of characters. \d+ matches one or more numerals (if you want to exclude non western numerals, use [0-9] instead of \d).
Here's the (more efficient) non-Regex approach:
string text = "abc xyz: ID# 1000123, this is test, test 1, test 1234, ";
string id = null;
int idIndex = text.IndexOf("ID# ");
if(idIndex != -1)
{
idIndex += "ID# ".Length;
int commaIndex = text.IndexOf(',', idIndex);
if(commaIndex != -1)
id = text.Substring(idIndex, commaIndex - idIndex);
else
id = text.Substring(idIndex);
}
Try this reg, it should take exactly the number
(?<=ID\#\s)\d+(?=\,)
if finds the number after ID# and before ,
Gets the number (i.e. all chars up to, but not including, the first comma) ...
"ID# ([^,]*),"
If you want to make it numbers explicity then...
"ID# ([0-9]*),"
For a non-regex version ...
string text = "abc xyz: ID# 1000123, this is test, test 1, test 1234, ";
string num = text.Split(new Char[] {','})[0].Split(new Char[] {' '})[3];
"ID# (.*), "to"ID# (.*?), ".