Returning array from simple function is empty

Question

I have the following function:

function getUser($user_id){

    $mysqli = dbConnect();

    $gu = "select * from users where user_id = '$user_id'";
    $ru = $mysqli->query($gu);

    $user = $ru->fetch_array();

    return $user;
}

Which is called eg:

$user_id =  $_SESSION[user_id];

getUser($user_id);

Then I want to simply echo fields i want, e.g. name. But, when I try the following, it returns empty

echo "users name is $user['name']"; // returns: users name is

Is there a better way to do this?

UPDATE Also tried the following but still empty:

function getUser($user_id){

    $mysqli = dbConnect();

    $gu = "select * from users where user_id = '$user_id'";
    $ru = $mysqli->query($gu);

    $user = array();
    while($row = $ru->fetch_array()) {
        $user[] = $row;
    }

    return $user;
}

You doesn't store the result of getUser(). Check the answer of @CodeBird — hek2mgl
– hek2mgl, Commented May 12, 2013 at 20:14
The comments/answers already posted are correct. A couple of other things: 1) What is the type of the user_id column? You're querying it like it's a string type. 2) Have you tried checking into the return value of your fetch_array() call? var_dump() or print_r() if you've no debugger handy. — marramgrass
– marramgrass, Commented May 12, 2013 at 20:19

CodeBird · Accepted Answer · 2013-05-12 19:57:40Z

2

your line:

getUser($user_id);

should be:

$user=getUser($user_id);

This way you'll be setting $user to the array the getUser returns, then you can use it.

answered May 12, 2013 at 19:57

CodeBird

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Comments

SAVAFA · Accepted Answer · 2013-05-12 20:00:17Z

0

Remove the single quotes when printing an array, you echo may needed to be like:

echo "users name is $user[name]";

answered May 12, 2013 at 20:00

SAVAFA

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