foreach($group as $key=>$value)
{
echo $key. " = " .$value. "<br>";
}
For example:
doc1 = 8
doc2 = 7
doc3 = 1
I want to count $value, so the result is 8+7+1 = 16. What should i do?
Thanks.
5 Answers
$sum = 0;
foreach($group as $key=>$value)
{
$sum+= $value;
}
echo $sum;
Comments
In your case IF you want to go with foreach loop than
$sum = 0;
foreach($group as $key => $value) {
$sum += $value;
}
echo $sum;
But if you want to go with direct sum of array than look on below for your solution :
$total = array_sum($group);
for only sum of array looping is time wasting.
http://php.net/manual/en/function.array-sum.php
array_sum — Calculate the sum of values in an array
<?php
$a = array(2, 4, 6, 8);
echo "sum(a) = " . array_sum($a) . "\n";
$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4);
echo "sum(b) = " . array_sum($b) . "\n";
?>
The above example will output:
sum(a) = 20
sum(b) = 6.9
Comments
2 Comments
Peter Chaula
I can imagine someone hasn't upvoted this. Everyone seems to be reinventing the wheel
Austin Brunkhorst
To be fair, the algorithm is so trivial sometimes people forget that things like this exist in the standard library. Sometimes SO gets locked into a mob mentality, up voting answers while ignoring others because the first one works.
$total=0;
foreach($group as $key=>$value)
{
echo $key. " = " .$value. "<br>";
$total+= $value;
}
echo $total;
Comments
$valueto it inside the loop. Seriously, this is a really elementary general beginner programming question; make sure you're clear on the real basic concepts before you try to go farther, since otherwise you're going to encounter a lot of things that won't make sense to you.