I'm quite new to regex. Not sure how to do the follow:
Replace ":p_id" with a specific value.
For example when I simply want to replace ":p_id1" with a value, it also replaced ":p_id10" with the same value which is not what I want.
It's also possible for the ":p_id"'s to have punctuation before or after them e.g. "=:p_id1)"
Any advice?
Use the \b (word boundary) operator
myString.replaceAll(":p_id1\\b","some replacement");
See Pattern > Boundary matchers
You could use a negative lookahead at the end of your Pattern.
For instance:
Pattern pattern = Pattern.compile(":p_id\\d(?!\\d)");
String example = ":p_id1 :p_id10";
Matcher matcher = pattern.matcher(example);
while (matcher.find()) System.out.println(matcher.group());
Output:
:p_id1
Here's the pattern I made:
^[=]{0,1}:p_id1\b[=]{0,1}
This matches strings like:
:p_id1
=:p_id1
:p_id1=
but doesn't match (for instance):
:p_id10
