For Loop Creation of new instance of Array in ActionScript 3

Question

Is there any way to create instances of array in a for loop?

Here's my code...

var recArrCon1:Array = new Array(50);
var recArrCon2:Array = new Array(50);
var recArrCon3:Array = new Array(50);
var recArrCon4:Array = new Array(50);
var recArrCon5:Array = new Array(50);
var recArrCon6:Array = new Array(50);
var recArrCon7:Array = new Array(50);
var recArrCon8:Array = new Array(50);

I want to make declaration in a dynamic way by a for loop. Thanks in advance.

By the way, I'm using AS3

Edit: The answer is (from Barış Uşaklı):

var recArrCons:Object = {};
for(var i:int=1; i<=8; i++) 
{
    recArrCons["recArrCon" + i] = new Array(50);
}

trace(recArrCons.recArrCon4); // 4th array

What language are we talking about?

Chief Wiggum
– Chief Wiggum

2013-05-15 01:36:50 +00:00
Commented May 15, 2013 at 1:36 — Chief Wiggum
– Chief Wiggum, Commented May 15, 2013 at 1:36

Barış Uşaklı · Accepted Answer · 2013-05-15 02:34:53Z

2

Make the class containing this code dynamic then you can create the names dynamically.

for(var i:int=1; i<=8; i++) 
{
    this["recArrCon" + i] = new Array(50);
}

trace(this.recArrCon4); // 4th array

Or you can store them in an Object like :

var recArrCons:Object = {};
for(var i:int=1; i<=8; i++) 
{
    recArrCons["recArrCon" + i] = new Array(50);
}

trace(recArrCons.recArrCon4); // 4th array

edited May 15, 2013 at 2:34

answered May 15, 2013 at 2:14

Barış Uşaklı

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5 Comments

Barış Uşaklı Over a year ago

Edited my answer, it will only work if the containing class is dynamic

flashMark Over a year ago

Thank you sir... This is the best and cleanest way I can derive new instances of Array bu storing it to an Object. Thanks a lot.

flashMark Over a year ago

Sir, how about accessing each object.. I'm trying to insert value on those arrays with dynamic variable String added in name like this... var firstPName:String = "2"; for(var i:int=1; i <= 50; i++){ if(!this["recArrCons.recArrCon"+firstPName][i]){ this["recArrCons.recArrCon"+firstPName][i] = secondPName; break; } } It receives error on runtime. Though, I can access the values by directly calling them according to their names without "this[]".

Barış Uşaklı Over a year ago

recArrCons['recArrCon'+ firstPName][i] will give the ith element. It will be much more readable if you store a reference to the array though like : var arr:Array = recArrCons['recArrCon'+firstPName] and ten arr[i]

flashMark Over a year ago

okay sir.. thanks alot. I now understand it that way... recArrCons['recArrCon'+ firstPName][i] ... I'll try this first.

Marty · Accepted Answer · 2013-05-15 02:40:04Z

0

I wouldn't create instances of Array the way you are, it's very messy. I suggest using a list of arrays like this:

var arrays:Vector.<Array> = new <Array>[];
for(var i = 0; i < 8; i++)
{
   arrays.push(new Array(50));
}

Where you would access an array like this:

var inner:Array = arrays[2];

And values of the arrays using [x][y]:

trace(arrays[0][0]);

edited May 15, 2013 at 2:40

answered May 15, 2013 at 2:33

Marty

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2 Comments

flashMark Over a year ago

it's a 2 dimensional array. I have think this way too. But, base on the need of my application, it may cause some problem. By the way Sir Marty. Thank you for response with my question. I'll get to use it someday.

Marty Over a year ago

@flashMark Sounds fair, just be cautious of polluting the current scope with a bunch of arrays.

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