Php $_POST[] method not working with certain input name

Question

I am working on a form and it looks like this

<form name="project" method="post" action="result.php">
   Address: <input name="address[line1]" type="text"/>
</form>

In the result.php, I use the following code to get the input

<?php echo (isset ($_POST['address[line1]') ?  $_POST ['address [line1]'] : 'fail') ?>

However, I keep getting 'fail' on my page instead of catching the input address[line1], and the strange thing is when I change the name to "addressLine1" it works perfectly, can anyone advise me on this?

I am new to web development and I am pretty confused now.

Brackets [] are used for arrays. Plus, you're missing an if for your isset. — Funk Forty Niner
– Funk Forty Niner, Commented May 15, 2013 at 3:02
Thanks! Also just realize this by googling around! BTW, my isset works and I work this out by referring to davidwalsh.name/php-ternary-examples, any issue with this? @Fred — Bob
– Bob, Commented May 15, 2013 at 3:19

Mayank K. Swami · Accepted Answer · 2013-05-15 02:49:30Z

4

what you are after is $_POST["address"]["line1"] the array notation in the field name results in an array being created on the PHP side. In the future you can always just var_dump or print_r the contents of $_POST to see what is happening.

edited May 15, 2013 at 2:49

Mayank K. Swami

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answered May 15, 2013 at 2:46

Orangepill

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1 Comment

Bob Over a year ago

Thanks so much. var_dump is quite useful!

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