I have a list containing the numbers 25-1. I'm trying to print it out like a gameboard, where all the numbers match up:
I found out how to add the lines to the list by doing this:
_b = map(str, board)
_board = ' | '.join(_b)
and I know how to print 5 numbers on each line.. but I'm having trouble getting all the numbers to line up. Is there a way to do this?
If you know how long the longest number is going to be, you can use any of these methods:
With the string "5" and a desired width of 3 characters:
str.rjust(3) will give the string ' 5'str.ljust(3) will give the string '5 'str.center(3) will give the string ' 5 '.I tend to like rjust for numbers, as it lines up the places like you learn how to do long addition in elementary school, and that makes me happy ;)
That leaves you with something like:
_b = map(lambda x: str(x).rjust(3), board)
_board = ' | '.join(_b)
or alternately, with generator expressions:
_board = ' | '.join(str(x).rjust(3) for x in board)
board = range(1,26) #the gameboard
for row in [board[i:i+5] for i in range(0,22,5)]: #go over chunks of five
print('|'.join(["{:<2}".format(n) for n in row])+"|") #justify each number, join by |
print("-"*15) #print the -'s
Produces
>>>
1 |2 |3 |4 |5 |
---------------
6 |7 |8 |9 |10|
---------------
11|12|13|14|15|
---------------
16|17|18|19|20|
---------------
21|22|23|24|25|
---------------
Or using the grouper recipe as @abarnert suggested:
for row in grouper(5, board):
itertools, why not just for row in grouper(5, board): (with the recipe from the docs)?
Just for fun, here's a 1-liner that creates the numbered rows:
['|'.join([str(y).center(4) for y in x]) for x in map(None,*[reversed(range(1,26))]*5)]
Breaking it up a little, adding rows, still not a clean answer:
nums = map(None,*[reversed(range(1,26))]*5)
rows = ['|'.join([str(y).center(4) for y in x]) for x in nums]
board = ('\n'+'-'*len(rows[0])+'\n').join(rows)
print board
board = range(25, 0, -1)
def printLine():
print
print "------------------------"
for c in board:
print str(c).ljust(2),'|',
if c % 5 == 1:
printLine()
That piece of code should work.
str.ljust(str(c), 2) instead of just str(c).ljust(2)? Sure, you can call methods that way in Python, but why?
board = range(25, 0, -1)—then you don't need the sort.itertools-style generator transformations in C++, or an ObjC doWithBlock:^{…} internal iteration in Python, or a C++-style std::transform into a back_iterator in JavaScript, etc., so I don't try.A somewhat generalized solution, for a 2D matrix representation:
board = [ [22, 1 , 33], [41, 121, 313], [0, 1, 123112312] ]
maxd = max(len(str(v)) for b in board for v in b) + 1
l = []
for b in board:
l.append("|"+" |".join([ '{n: {w}}'.format(n=v, w=maxd) for v in b]) + " |")
sepl = "\n" + '-'*len(l[0]) + "\n"
print sepl, sepl.join(l), sepl
I tried a different approach using list comprehensions and the String Format Mini-Language.
boardout = "".join([" {:<2} |".format(x) if (x-1)%5>0 else " {:<2} |\n{}\n".format(x, "-"*25) for x in range(25,0,-1)])
print boardout
This should produce similar output to the OP's expected output. EDIT: Thanks to @abarnert for the shifting tip.
{:<2}.