PHP file_get_contents with if/else

Question

On this link I was learning about file_get_contents and I'd like to incorporate it into a simple if/else statement but can't seem to get it correct.

I'd like to check if the file exists and if not, display a no_image.jpg graphic.

My struggle is that the tag already has a PHP echo so it is causing the snippet to stop working. How do I format the if/else while still haveing the use the dynamic value from the echo if file_get_contents is true?

Currently I have a simple tag like this:

<img width="200" height="150" src="images/<?php echo(rawurlencode($row['MLS_NUMBER'])); ?>_1.jpg" alt="" align="left" vspace="3" hspace="3" />

SachinGutte · Accepted Answer · 2013-05-22 16:03:47Z

6

Basically:

<?php

if (file_exists(...)) {
  $path = ...;
} else {
  $path = 'no_image.jpg';
}
?>

<img src="images/<?php echo $path; ?>" />

//add a semicolon after echo $path otherwise it won't work

edited May 22, 2013 at 16:03

SachinGutte

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answered May 22, 2013 at 15:57

Marc B

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Comments

ksorbo · Accepted Answer · 2013-05-22 16:03:54Z

0

Assuming you are looking for a jpg file based on $row['MLS_NUMBER']

<img width="200" height="150" src="images/
<?php 
 if (file_exists($row['MLS_NUMBER']) {
       echo(rawurlencode($row['MLS_NUMBER'])).'_1.jpg';
     } else {
       echo "no_image.jpg";
     }
 ?>" alt="" align="left" vspace="3" hspace="3" />

answered May 22, 2013 at 16:03

ksorbo

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3 Comments

Rocco The Taco Over a year ago

How does php know what directory and file extension to looks for with file exists? Don't you need to specify path and .jpg...otherwise it is just looking for the number? I tried this with no luck?

Rocco The Taco Over a year ago

I tried this with no luck? if (file_exists(."/images/".$row['MLS_NUMBER']."_1.jpg"))

ksorbo Over a year ago

@Rocco. The code given is an example. I don't know which jpg you want to show. PHP will NOT know where your graphics are, so you need to add a directory to $row['MLS_NUMBER']. So if for example you have an a graphic named /images/234666234_1.jpg where 234666234 is the MLS number coming in via $row array, then you would write if(file_exists("/images/{$row['MLS_NUMBER']}_1.jpg") etc. Your code may have failed because of the additional . (dot) in the file_exists(."/images line.

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