iOS send string to JSON Server

Question

im struggling this for several hours, i want to send a json string to an asp.net server, but i always get null response. Is there anything wrong with my code?or problem in the server side? thanks a lot..

(url is hidden for security only), and this is the update code..

NSError *error;


NSDictionary* jsonDict = @{@"FundCode": @(1), @"TotalAmount":@(1000000), @"PaymentType":@(0), @"Bank":@"AAA BANK",@"BankAccountNo": @"123456789",@"Amount":@"1000000",
                           @"DepositFile":@"asset.PNG"};

NSData* postData = [NSJSONSerialization dataWithJSONObject:jsonDict options:kNilOptions error:&error];


NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

NSURL *url1 = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.url.com"]];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url1];
[request setHTTPMethod:@"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:postData];

Instead of passing nil in NSURLConnection sendSynchronousRequest:request returningResponse:&response error:nil]; pass a NSError* object and try to print the error. — kaar3k
– kaar3k, Commented May 24, 2013 at 4:53
Please verify your json using jsonlint.com There might be problem in json also. — Prasad Devadiga
– Prasad Devadiga, Commented May 24, 2013 at 4:54
your technique looks vulnerable. Error prone. Check my proper method here — Alphapico
– Alphapico, Commented May 28, 2013 at 9:45

Thomas Zoechling · Accepted Answer · 2013-05-24 05:01:44Z

2

You could try to use Cocoa's built-in JSON serialization to obtain your JSON data instead of providing an escaped string yourself. This rules out improper escaping etc.

NSError* error = nil;
NSDictionary* jsonDict = @{@"FundCode": @(1), @"TotalAmount":@(1000000), @"PaymentType":@(0), @"Bank":@"AAA BANK"};
NSData* postData = [NSJSONSerialization dataWithJSONObject:jsonDict options:kNilOptions error:&error];

Please note, that I didn't specify all keys - You'd need to complete the dictionary before sending the request.

answered May 24, 2013 at 5:01

Thomas Zoechling

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6 Comments

user2373192 Over a year ago

I already tried, but still no response..still no luck..please see my update code...

Thomas Zoechling Over a year ago

Can you pass in an &error object to your sendSynchronousRequest call and log it to the console. Maybe the JSON is OK but the request has some other issues?

user2373192 Over a year ago

hi, this is the response from the server { TopUpOnlineMessage = " - "; }

Thomas Zoechling Over a year ago

In your previous comment you said, that you still get no response but the string you posted looks like a perfectly valid JSON response?

user2373192 Over a year ago

Hi weichsel, currently we tested by sending again the json string, so the response must be the string i sent, the fund code, totalamount, etc.if my code is ok, is there possibility the problem on the server?thanks

|

Purushottam Sen · Accepted Answer · 2013-05-24 05:08:07Z

1

friend you are passing wrong method(as u sending it just as a NSString) for JSON use this method

NSError* errorJson = nil;
NSDictionary* jsonDict = @{@"FundCode": @(1), @"TotalAmount":@(1000000), @"PaymentType":@(0), @"Bank":@"AAA BANK",@"BankAccountNo": @"123456789",@"Amount":@@"1000000",
@"DepositFile":@"asset.PNG"};
NSData* postData = [NSJSONSerialization dataWithJSONObject:jsonDict options:kNilOptions error:&errorJson];

Hope this helps..

answered May 24, 2013 at 5:08

Purushottam Sen

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Comments

Prince Kumar Sharma · Accepted Answer · 2013-05-24 05:08:14Z

0

You can also use NSKeyArchiever to encode NSDictionary json to postData as given below

NSMutableDictionary *postDix=[[NSMutableDictionary alloc] init];
[postDix setValue:@"1" forKey:@"FundCode"];
[postDix setValue:@"1000000" forKey:@"TotalAmount"];
[postDix setValue:@"0" forKey:@"PaymentType"];    //etc

NSMutableData *postData = [[NSMutableData alloc] init];
NSKeyedArchiver *archiver = [[NSKeyedArchiver alloc] initForWritingWithMutableData:postData];
[archiver encodeObject:postDix forKey:@"json"];
[archiver finishEncoding];

answered May 24, 2013 at 5:08

Prince Kumar Sharma

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