String tokenizer to array java

Question

I'm trying to import data from a file to array using string tokenizer.

Data format in file is

AA,BB,CC
AA,BB,CC

But i keep getting error

Exception in thread "main" java.util.NoSuchElementException
    at java.util.StringTokenizer.nextToken(StringTokenizer.java:349)
    at java.util.StringTokenizer.nextElement(StringTokenizer.java:407)
    at main.main(main.java:36)

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
import java.util.StringTokenizer;


public class main {
public static void main(String[] args) throws FileNotFoundException {

    Scanner input;
    String line;
    int x=0;
    String [] cName = new String [100];
    String [] cMascot = new String [100];
    String [] cAlias = new String [100];





         input = new Scanner(new File("test.txt"));

         while(input.hasNextLine()) {

             line = input.nextLine();
             StringTokenizer strings = new StringTokenizer(line,",");

             while (strings.hasMoreElements()) {
                 cName[x] = strings.nextElement().toString();
                 cMascot[x] = strings.nextElement().toString();
                 cAlias[x] = strings.nextElement().toString();
                 x++;
             }

         }


}

}

So any help would be appreciated. I cant use array list so that out of the context

Shouldn't you check for hasMoreElements() before calling to each nextElement() ? — AllTooSir
– AllTooSir, Commented May 25, 2013 at 13:08
@fge I'm new to java so could tell me how would i go about it? — djEthen
– djEthen, Commented May 25, 2013 at 13:09
@the new idiot i do check for more elements "strings.hasMoreElements()" — djEthen
– djEthen, Commented May 25, 2013 at 13:11

IvanNik · Accepted Answer · 2013-05-25 13:10:43Z

2

you can't call .nextElement() many times in while statement; befor each of them .hasNextLine() must be called

answered May 25, 2013 at 13:10

IvanNik

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2 Comments

djEthen Over a year ago

Yea. I got that now.. Thanks :)

Ravi K Thapliyal Over a year ago

Did you mean hasMoreElements()?

xagyg · Accepted Answer · 2013-05-25 13:10:15Z

1

I suggest you use readLine and split ...

public static void main(String[] args) throws FileNotFoundException {

    String line;
    int x=0;
    String [] cName = new String [100];
    String [] cMascot = new String [100];
    String [] cAlias = new String [100];

    try (BufferedReader input = new BufferedReader(new FileStreamReader("test.txt"))) {

         while ((line = input.readLine())!=null) {

             cName[x] = line.split(",")[0];
             cMascot[x] = line.split(",")[1];
             cAlias[x] = line.split(",")[2];
             x++;
         }
    }

}

answered May 25, 2013 at 13:10

xagyg

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5 Comments

djEthen Over a year ago

Quick question: String [] cName = new String [100]; say i dont know if need i need 100 array size, whats the best way to make it dynamic, so if i have 105elements, i can still save them in array

Pshemo Over a year ago

@user2291480 if you need dynamic array then use ArrayList.

djEthen Over a year ago

Any way without ArrayList?

djEthen Over a year ago

Hey how do i cast "year[z] = line.split(",")[0];" to int?

Pshemo Over a year ago

@user2291480 Try Integer.parseInt(line.split(",")[0])

AtulS · Accepted Answer · 2013-05-25 15:09:00Z

0

You can have below code useful too :

public static void main(String[] args) throws FileNotFoundException {

    Scanner input;
    String line;

    String cMascot = null;
    String cAlias = null;
    String cName = null;

    input = new Scanner(new File("test.txt"));
    while (input.hasNextLine()) {
        line = input.nextLine();
        StringTokenizer strings = new StringTokenizer(line, ",");

        while (strings.hasMoreElements()) {
            cName = strings.nextToken();
            cMascot = strings.nextToken();
            cAlias = strings.nextToken();
            System.out.println("cName :" + cName);
            System.out.println("cMascot :" + cMascot);
            System.out.println("cAlias :" + cAlias);
        }
    }

}

answered May 25, 2013 at 15:09

AtulS

1

1 Comment

djEthen Over a year ago

Hey, thansk for that but the Strings have to be arrays.

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