php in_array() or array_search() not working [duplicate]

Question

I am using a simple php script to look for an element in an array like

    $restricted = array('root/base', 'root2' ); 
    print_r($restricted);
    if( array_search('root/base', $restricted) ){
        echo "1";
    } else {
        echo "0";
    }

But I am always getting the following output

Array ( [0] => root/base [1] => root2 ) 0

This means that the array_search is failing to find the element in the given array. Can anybody show some light on whats happening?

I tried to replace array_search() with in_array() also. But that too returned the same error.

This isn't a duplicate question -- this person's problem is mistaking the value 0 for FALSE. The OP's problem in the "duplicate question" cited is mistaking arrays for comma-separated strings. — Jan
– Jan, Commented May 14, 2015 at 22:51

Baba · Accepted Answer · 2013-05-25 14:03:21Z

23

From PHP DOC

array_search — Searches the array for a given value and returns the corresponding key if successful

The index is 0 that is why you think its fails

Use

array_search('root/base', $restricted) !== false

answered May 25, 2013 at 14:03

Baba

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2 Comments

rahul Ram Over a year ago

but why in_array() fails?

Baba Over a year ago

i don't see in_array in your example but see eval.in/31491

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