Adding XML sub elements to an ArrayList with DOM4J

Question

here's a sample of my XML file:

<agregator1 id="CSP">
    <id>int</id>
    <type>string</type>
</agregator1>
<agregator1 id="Microgrid">     
    <id>int</id>
    <type>string</type>
</agregator1>

I've never worked with DOM4J and I've read the documentation but I can't seem to get the sub-elements into ArrayList's, I'm trying to do the following:

arrayList1: id, type
arrayList2: int, string

here's my code:

for ( Iterator i = root.elementIterator(); i.hasNext(); ) {
    Element foo = (Element) i.next();
    if(foo.attributeValue("id").toString().equals("CSP"))
    {
      //what am I missing here?
    }
}

I've searched a lot, and I can't find any solution since I can't do foo.getChildNodes().

Any sugestions?

EDIT: I need to get the node names without using elementText(String) (or anything like this) because I need my code to work even if the XML file is changed, without editing my code.

sghaier ali · Accepted Answer · 2017-02-08 10:18:39Z

1

I can help you with this 2 solutions:

Methode 1: select all element agregator1 after that verify only attributeValue if equal a CSP.

Element root = document.getRootElement();
List<Element> listElement = root.selectNodes("./agregator1");
if (listElement != null) {
    for (int j = 0; j < listElement.size(); j++) {
        Element el = listElement.get(j);
        String attrValue = el.attributeValue("id", "");
        if (attrValue.length() > 0 && attrValue.equals("CSP")) {
            // do your code
        }
    }
}
else {
    // element not found
}

Methode 2: do this in just 1 line, use xpath

Element rootElement = doc.getRootElement();
List<Element> elementNeeded = rootElement.selectNodes("./agregator1[@id='CSP']");
if (elementNeeded != null && elementNeeded.size() > 0) {
    // element found do your code
}
else {
    // element not found
}

edited Feb 8, 2017 at 10:18

user6420561

answered May 28, 2013 at 8:23

sghaier ali

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3 Comments

SaintLike Over a year ago

Can you do that? List doesn't take parameters

SaintLike Over a year ago

Isn't that the exact same thing I've done? I need a way to get the agregator1 child nodes...

sghaier ali Over a year ago

for the first methode: the element "el" (Element el = listElement.get(j);) has all child nodes for get one just do this: el.selectnodes("./[NameOfElementYouLike]") ==> your get list for all element with name = [NameOfElementYouLike]. 2- for the second methode you current element is "elementNeeded": this element has all childs nodes

SaintLike · Accepted Answer · 2013-05-28 12:42:16Z

I solved my problem. Thanks to all who tryed to help. To all the people who are searching for a similar solution, here's my code:

This is the above method, completed:

public static ArrayList<Element> readSubElements()
   {
       ArrayList<Element> subElements = new ArrayList<>();

        Element root = configs.XMLreaderDOM4J.getDoc().getRootElement();
        for (Iterator it = root.elementIterator(); it.hasNext();){
            Element foo = (Element) it.next();
            if(foo.attributeValue("id").equals("VPP"))
            {
               for (Iterator it2 = foo.elementIterator(); it2.hasNext(); )
               {
                  Element temp = (Element) it2.next();
                   subElements.add(temp);
                   System.out.println(""+temp);
               }
            }
        }

       return subElements;        
   }

And a new method I've created:

public static void getTagNames() {

   ArrayList<Element> elements = readSubElements();
   ArrayList<String> list1 = new ArrayList<>();
   ArrayList<String> list2 = new ArrayList<>();
   setSize(elements.size());

   for (Iterator it = elements.iterator(); it.hasNext();) {
      Element entry = (Element) it.next();
      list1.add(entry.getQualifiedName());
      list2.add(entry.getText());
   }

   setTagNamesAL(list1);
   setTagContentAL(list2);
}

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